The reaction of $CH_3-CH=CH-C_6H_4-OH$ with $HBr$ gives:

  • A
    $CH_3-CHBr-CH_2-C_6H_4-OH$
  • B
    $CH_3-CH_2-CHBr-C_6H_4-OH$
  • C
    $CH_3-CHBr-CH_2-C_6H_4-Br$
  • D
    $CH_3-CH_2-CHBr-C_6H_4-Br$

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